document.write( "Question 106371This question is from textbook Beginning Algebra
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document.write( ": Question 54. This is dealing with adding/subtracting rational expressions \r
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document.write( "(the below are supposed to be fractions, but I didn't know how to write them in here so you'd understand. Sorry if it doesn't come across pretty)\r
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document.write( " 2 - 3
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document.write( "___ ___\r
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document.write( "5w+10 2w-4\r
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document.write( "This is what I have so far, but I am a bit confused.\r
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document.write( "I know that I need to find the LCD. Because of the numerators the way they are, I know that they are:\r
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document.write( "5w+10 which can be factored to 5(w+2)
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document.write( "2w-4 which can be factored to 2(w-2)\r
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document.write( "So, still they don't match as they have in other equations. \r
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document.write( "2*2(w-2) - 3*5(w+2)
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document.write( "___________ __________
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document.write( "5(w+2)*2(w-2) 2(w-2)*5(w+2) Not sure if I did that right\r
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document.write( "This then becomes:\r
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document.write( "4(w-2) - 15(w+2)
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document.write( "_________ __________
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document.write( "5(w+2)*2(w-2) 2(w-2)*5(w+2)\r
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document.write( "I am going to stop there, because I have a horrible feeling that I am way off track. Can you please help?
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Algebra.Com's Answer #77381 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2 - 3 \n" ); document.write( "___ ___\r \n" ); document.write( "\n" ); document.write( "5w+10 2w-4 \n" ); document.write( "-----------------\r \n" ); document.write( "\n" ); document.write( "Factor the denominators:\r \n" ); document.write( "\n" ); document.write( "[2/(5(w+2)] - [3/(2(w-2)]\r \n" ); document.write( "\n" ); document.write( "---------- \n" ); document.write( "You need a common denominator. \n" ); document.write( "------------- \n" ); document.write( "The least common denominator (lcd) is 10(w+2)(w-2) \n" ); document.write( "--------------- \n" ); document.write( "Rewrite each fraction with the lcd as its denominator: \n" ); document.write( "----------- \n" ); document.write( "[2*2(w-2)]/lcd - [3*5(w+2)]/lcd\r \n" ); document.write( "\n" ); document.write( "--------------- \n" ); document.write( "Since the denominators are now the same you work with the numerators:\r \n" ); document.write( "\n" ); document.write( "= [4(w-2)-15(w+2)]/lcd\r \n" ); document.write( "\n" ); document.write( "Simplify the numerator:\r \n" ); document.write( "\n" ); document.write( "= [-11w-38]/[10(w+2)(w-2)\r \n" ); document.write( "\n" ); document.write( "This could be written as:\r \n" ); document.write( "\n" ); document.write( "= [-11w-38]/[10(w^2-4)]\r \n" ); document.write( "\n" ); document.write( "================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |