document.write( "Question 106358: Electrical Trades: The sum of three voltages in a circuit is 38 volts. The middle-sized one is 2 volts more than the smallest. The largest is 6 volts more than the smallest. What is the value of each voltage? \n" ); document.write( "
Algebra.Com's Answer #77379 by solver91311(24713)\"\" \"About 
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Since the three voltages are compared in terms of the smallest, let x = Vs.\r
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\n" ); document.write( "\n" ); document.write( "The medium voltage is 2 volts larger than the smallest, so x + 2 = Vm\r
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\n" ); document.write( "\n" ); document.write( "And the largest voltage is 6 volts larger than the smallest, so x + 6 = Vl\r
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\n" ); document.write( "\n" ); document.write( "\"Vs+%2B+Vm+%2B+Vl+=+38+volts\" or,\r
\n" ); document.write( "\n" ); document.write( "\"x+%2B+%28+x+%2B+2%29+%2B+%28x+%2B+6%29+=+38\"\r
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\n" ); document.write( "\n" ); document.write( "Simplifying,\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+8+=+38\"
\n" ); document.write( "\"3x=30\"
\n" ); document.write( "\"x+=+10\", hence the smallest voltage is 10 volts, the medium voltage is 12 volts, and the largest voltage is 16 volts.\r
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\n" ); document.write( "\n" ); document.write( "Checking the answer:\r
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\n" ); document.write( "\n" ); document.write( "\"+10+%2B+12+%2B+16+=+38\" check
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