document.write( "Question 1151898: A club is choosing 2 members to serve on a committee. The club has nominated 1 women and 3 men. Based on chance alone, what is the probability that one woman and one man will be chosen to be on the committee? \n" ); document.write( "

Algebra.Com's Answer #773767 by ikleyn(52798) $\"\"$ $\"About$

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document.write( "From nominated 1 women and 3 men, the pair of persons to serve on a committee can be chosen by   =  = 2*3 = 6 different ways.\r\n" );
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document.write( "    Here 4 = 1 + 3 is the total number of nominated persons.\r\n" );
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document.write( "We consider here non-ordered pairs, since the difference in their positions/duties is not specified.\r\n" );
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document.write( "Of this total number of pairs, the pairs containing one woman can be selected by 3 different ways.\r\n" );
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document.write( "So, the probability under the question is   = .    ANSWER\r\n" );
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