document.write( "Question 1151870: What is the equation formed from the families of straight lines tangent to the parabola \n" );
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Algebra.Com's Answer #773762 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The graph of \n" ); document.write( "The equation for the portion of the graph with y positive is \n" ); document.write( " \n" ); document.write( "Take the derivative, using the power and chain rules, to find the slope: \n" ); document.write( " \n" ); document.write( "For each value of x, the tangent line will have slope \n" ); document.write( "For a given value of x, find the expression for the y-intercept b for the tangent line with \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So for a given value of x, the tangent line in the first quadrant has slope \n" ); document.write( "The equation is then \n" ); document.write( " \n" ); document.write( "Choosing some \"nice\" values of x that make \n" ); document.write( "x = 1/2: \n" ); document.write( "x = 2: \n" ); document.write( "x = 9/2: \n" ); document.write( "x = 8: \n" ); document.write( "And then there are corresponding tangent lines on the other branch of the parabola: \n" ); document.write( "x = 1/2: \n" ); document.write( "x = 2: \n" ); document.write( "x = 9/2: \n" ); document.write( "x = 8: \n" ); document.write( "A graph of the parabola and the tangent lines for x=1/2 -- x+1/2 and -x-1/2: \n" ); document.write( " \n" ); document.write( "A graph of the parabola and the tangent lines for x=2 -- (1/2)x+1 and (-1/2)x-1: \n" ); document.write( " \n" ); document.write( "A graph of the parabola and the tangent lines for x=8 -- (1/4)x+2 and (-1/4)x-2: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |