document.write( "Question 1151870: What is the equation formed from the families of straight lines tangent to the parabola \"y%5E2=2x\" \n" ); document.write( "
Algebra.Com's Answer #773762 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The graph of \"y%5E2=2x\" is symmetrical with respect to the x-axis. So we can find the equations of the tangent lines for the portion of the graph with y positive; then any tangent line with equation \"y=mx%2Bb\" will have a corresponding tangent line with equation \"y=-%28mx%2Bb%29\", or \"y=-mx-b\".

\n" ); document.write( "The equation for the portion of the graph with y positive is

\n" ); document.write( "\"y+=+sqrt%282x%29+=+%282x%29%5E%281%2F2%29\"

\n" ); document.write( "Take the derivative, using the power and chain rules, to find the slope:

\n" ); document.write( "\"dy%2Fdx+=%281%2F2%29%282x%29%5E%28-1%2F2%29%282%29+=+%282x%29%5E%28-1%2F2%29\"

\n" ); document.write( "For each value of x, the tangent line will have slope \"%282x%29%5E%28-1%2F2%29\"; and the y value will be \"%282x%29%5E%281%2F2%29\"

\n" ); document.write( "For a given value of x, find the expression for the y-intercept b for the tangent line with \"y+=+%282x%29%5E%281%2F2%29\" and slope \"%282x%29%5E%28-1%2F2%29\".

\n" ); document.write( "\"y+=+mx%2Bb\"
\n" ); document.write( "\"%282x%29%5E%281%2F2%29+=+%28%282x%29%5E%28-1%2F2%29%29x+%2B+b\"
\n" ); document.write( "\"sqrt%282%29%2Asqrt%28x%29+=+%281%2F%28sqrt%282%29%2Asqrt%28x%29%29%29%2Ax+%2B+b\"
\n" ); document.write( "\"b+=+sqrt%282%29%2Asqrt%28x%29+-+%281%2F%28sqrt%282%29%2Asqrt%28x%29%29%29%2Ax\"
\n" ); document.write( "\"b+=+sqrt%282%29%2Asqrt%28x%29+-+%28sqrt%28x%29%2Fsqrt%282%29%29\"
\n" ); document.write( "\"b+=+sqrt%28x%29%28sqrt%282%29-1%2Fsqrt%282%29%29\"
\n" ); document.write( "\"b+=+sqrt%28x%29%282%2Fsqrt%282%29-1%2Fsqrt%282%29%29\"
\n" ); document.write( "\"b+=+sqrt%28x%29%281%2Fsqrt%282%29%29\"
\n" ); document.write( "\"b+=+sqrt%28x%2F2%29\"

\n" ); document.write( "So for a given value of x, the tangent line in the first quadrant has slope \"1%2Fsqrt%282x%29\" and y-intercept \"sqrt%28x%2F2%29\".

\n" ); document.write( "The equation is then

\n" ); document.write( "\"y+=+%281%2Fsqrt%282x%29%29x+%2B+sqrt%28x%2F2%29\"

\n" ); document.write( "Choosing some \"nice\" values of x that make \"sqrt%282x%29\" and \"sqrt%28x%2F2%29\" rational....

\n" ); document.write( "x = 1/2: \"y+=+x%2B1%2F2\"
\n" ); document.write( "x = 2: \"y+=+%281%2F2%29x%2B1\"
\n" ); document.write( "x = 9/2: \"y+=+%281%2F3%29x%2B3%2F2\"
\n" ); document.write( "x = 8: \"y+=+%281%2F4%29%2B2\"

\n" ); document.write( "And then there are corresponding tangent lines on the other branch of the parabola:

\n" ); document.write( "x = 1/2: \"y+=+-x-1%2F2\"
\n" ); document.write( "x = 2: \"y+=+%28-1%2F2%29x-1\"
\n" ); document.write( "x = 9/2: \"y+=+%28-1%2F3%29x-3%2F2\"
\n" ); document.write( "x = 8: \"y+=+%28-1%2F4%29-2\"

\n" ); document.write( "A graph of the parabola and the tangent lines for x=1/2 -- x+1/2 and -x-1/2:

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\n" ); document.write( "A graph of the parabola and the tangent lines for x=2 -- (1/2)x+1 and (-1/2)x-1:

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\n" ); document.write( "A graph of the parabola and the tangent lines for x=8 -- (1/4)x+2 and (-1/4)x-2:

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