document.write( "Question 1151870: What is the equation formed from the families of straight lines tangent to the parabola \"y%5E2=2x\" \n" ); document.write( "
Algebra.Com's Answer #773758 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the equation of tangent line that we seek is \"y=mx%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "if \"y%5E2=2x\", then\r
\n" ); document.write( "\n" ); document.write( "Since both the abscissa (\"x\") and ordinate (\"y\") are positive, we can try to work with the positive half of the function when solving for \"y\":\r
\n" ); document.write( "\n" ); document.write( "\"y=sqrt%282x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%282x%29%5E%281%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "To find the line tangent to it, we find the derivative\r
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=%281%2F2%29%28sqrt%282%29%2Fsqrt%28x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Plug in \"x=2\" to get the slope\r
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=%281%2F2%29%28sqrt%282%29%2Fsqrt%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx=1%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "To get the y-intercept, plug in the numbers in the slope-intercept form linear equation\r
\n" ); document.write( "\n" ); document.write( "\"y=mx%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "when \"x=2\"=>\"y%5E2=2%2A2\"=>\"y=sqrt%284%29=2\", and tangent will touch parabola at point (\"2\",\"2\")
\n" ); document.write( "we have\r
\n" ); document.write( "\n" ); document.write( "=>\"2=%281%2F2%29%2A2%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "=>\"2=1%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "=>\"b=1\"\r
\n" ); document.write( "\n" ); document.write( "So the equation is \"y=x%2F2%2B1\"\r
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