document.write( "Question 1151876: A study conducted among 29-year-old male, acetone levels werenormally distributed with a mean of 1070 and a standard deviation of 311 ppb. Find the probability that on a given day the subject’s acetone level is:
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document.write( "a. Between 700 and 1100 ppb
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document.write( "b. Over 1000 ppb
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document.write( "c. Under 600 ppb
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document.write( "d. Between 1000 and 1200 ppb \n" );
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Algebra.Com's Answer #773744 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! z for each of these is (x-mean)/sd \n" ); document.write( "for 700, z is -370/311 or -1.19 \n" ); document.write( "for 1000, it is -70/311 or -0.23 \n" ); document.write( "for 600, it is -470/311 or -1.51 \n" ); document.write( "for 1200 it is 130/311 or 0.42 \n" ); document.write( "for 1100 it is 30/311 or 0.10\r \n" ); document.write( "\n" ); document.write( "a. z between -1.19 and +0.10 so probability is 0.4228 \n" ); document.write( "b. over 1000 is z>-0.23 so probability is 0.5910 \n" ); document.write( "c. under 600 is z < -1.51 so probability is 0.0655 \n" ); document.write( "d. between 1000 and 1200 is z between -0.23 and +0.42 so probability is 0.2537 \n" ); document.write( " |