document.write( "Question 1151875: A company sold some equipment for $1950. This was 30% more than they paid for the equipment. What did the company pay for the equipment? \n" ); document.write( "
Algebra.Com's Answer #773733 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "x = original price
\n" ); document.write( "30% of x = 0.30*x
\n" ); document.write( "x + 0.30x = 1.30x = markup price = 1950\r
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\n" ); document.write( "\n" ); document.write( "1.30x = 1950
\n" ); document.write( "1.30x/1.30 = 1950/1.30 .... divide both sides by 1.30
\n" ); document.write( "x = 1500\r
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\n" ); document.write( "\n" ); document.write( "Answer: The original price was $1,500\r
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\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "Apply 30% to this
\n" ); document.write( "30% of 1500 = 0.30*1500 = 450
\n" ); document.write( "Add this to the original price
\n" ); document.write( "1500+450 = 1950
\n" ); document.write( "This is a longer way compared to calculating
\n" ); document.write( "1.30*x = 1.30*1500 = 1950
\n" ); document.write( "Either way the answer is confirmed
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