document.write( "Question 106362: help!!! my # is a multiple of 150 -- 9 is a factor of my # -- my # has 3 digits
\n" ); document.write( "the sum of the # in my digit is 9\r
\n" ); document.write( "\n" ); document.write( "I think you meant to say, as the last condition, that the sum of the digits in your number is 9. \n" ); document.write( "

Algebra.Com's Answer #77372 by solver91311(24713) $\"\"$ $\"About$

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Given that your number is a multiple of 150, you know that the number is greater than or equal to 150. Given that the number has 3 digits, you know that the number is less than 1000. The multiples of 150 between those limits are: 150, 300, 450, 600, 750, and 900.\r
\n" ); document.write( "\n" ); document.write( "Of these choices, two have 9 as a sum of the digits, 450 and 900. These two numbers also have 9 as a factor. 9 X 50 = 450, and 9 X 100 = 900. (In fact, any number that has 9 or a multiple of 9 as a sum of the digits is evenly divisible by 9). Hence, your problem has two equally valid answers, namely 450 and 900.\r
\n" ); document.write( "\n" ); document.write( "If you were expected to come up with one unique answer, then perhaps you forgot to provide one of the conditions.\r
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