document.write( "Question 1151848: Mayen is 5 years older than kate, and in 6 years time, mayen will be 3 times as old as what kate was 3 years ago. find their present age. \n" ); document.write( "
Algebra.Com's Answer #773700 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = Kate's age now
\n" ); document.write( "\"+x+%2B+5+\" = Mayen's age now
\n" ); document.write( "----------------------------------
\n" ); document.write( "\"+%28+x+%2B+5+%29+%2B+6+=+3%2A%28+x+-+3+%29+\"
\n" ); document.write( "\"+x+%2B+11+=+3x+-+9+\"
\n" ); document.write( "\"+2x+=+20+\"
\n" ); document.write( "\"+x+=+10+\"
\n" ); document.write( "and
\n" ); document.write( "\"+x+%2B+5+=+15+\"
\n" ); document.write( "----------------------
\n" ); document.write( "Kate is 10
\n" ); document.write( "Mayen is 15
\n" ); document.write( "-----------------
\n" ); document.write( "check:
\n" ); document.write( "In 6 yrs,
\n" ); document.write( "Kate will be 16
\n" ); document.write( "Mayen will be 21
\n" ); document.write( "--------------------
\n" ); document.write( "3 yrs ago, Kate was 7
\n" ); document.write( "3 times that is 21
\n" ); document.write( "Mayen was 21 also
\n" ); document.write( "OK
\n" ); document.write( "
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