document.write( "Question 15639: This problem has me stumped bcause I have 8 ounces already mixed and need to add to it to get 12 ounces. If I was just adding enough chocolate syrup to make it 42 percent, I would not be so confused. Here is the problem:
\n" ); document.write( "I want to make the perfect 12 ounce cup of chocolate milk. It requires that the mixture is 42% chocolate syrup. What I have right now is 8 ounces of milk/syrup mixture that I know contains 30% syrup. What must the syrup concentration be in the remaining mixture that I must add in order to achieve perfection? \n" ); document.write( "

Algebra.Com's Answer #7737 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
You'll need to set up the equation for the following:\r
\n" ); document.write( "\n" ); document.write( "8 oz of 30% syrup mixture + 4 oz of x% syrup mixture = 12 oz of 42% syrup mixture. Change the percents to decimals. The equation is:\r
\n" ); document.write( "\n" ); document.write( " $\"8%280.3%29+%2B+4%28x%29+=+12%280.42%29\"$ Simplify and solve for x.
\n" ); document.write( " $\"2.4+%2B+4x+=+5.04\"$ Subtract 2.4 from both sides.
\n" ); document.write( " $\"4x+=+2.64\"$ Divide both sides by 4.
\n" ); document.write( " $\"x+=+0.66\"$ Convert to a percent.\r
\n" ); document.write( "\n" ); document.write( "x = 66% \n" ); document.write( "

\n" );