document.write( "Question 1151840: A website advertises properties for sale. If the property is sold within the month, the website charges $140 for the advertisement, but if the property is not sold within the month, the website pays the advertiser $30. In a particular month, 49 advertisements were placed, and a total of $3120 was made across all advertising. Solve for y, the number of advertisements that resulted in a sale of the property. \n" ); document.write( "
Algebra.Com's Answer #773693 by ikleyn(52812)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let y = the number of advertisements that resulted in a sale of the property.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then 49-y is the number of advertising that did not result in a sale of the property.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Your equation to find y is this revenue equation\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 140*y - 30*(49-y) = 3120.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From the equation,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " y =\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |