document.write( "Question 1151819: A phone company offers two monthly plans. Plan A cost $16 plus an additional $0.16 for each minute of calls. Plan B cost $22 plus an additional $0.14 for each minute of calls. For what amount of calling do the two plans cost the same? What is the cost when the two plans cost the same? \n" ); document.write( "
Algebra.Com's Answer #773682 by Theo(13342)![]() ![]() You can put this solution on YOUR website! plan A costs $16 plus .16 per minute. \n" ); document.write( "plan B costs $22 plus an additional .14 per minute. \n" ); document.write( "let x = the number of minutes. \n" ); document.write( "let y = total cost. \n" ); document.write( "formula for plan A is y1 = 16 + .16 * x \n" ); document.write( "formula for plan B is y2 = 22 + .14 * x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the total costs are equal when y1 = y2. \n" ); document.write( "this means that 16 + .16 * x = 22 + .14 * x \n" ); document.write( "subtract 16 from both sides of this equation to get: \n" ); document.write( ".16 * x = 6 + .14 * x \n" ); document.write( "subtract .14 * x from both sides of this equation to get: \n" ); document.write( ".02 * x = 6 \n" ); document.write( "solve for x to get: \n" ); document.write( "x = 6 / .02 = 300.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the plans should be equal at 300 minutes of use.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "plan A would cost 16 + .16 * 300 = 64 dollars. \n" ); document.write( "plan B would cost 22 + .14 * 300 = 64 dollars.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the cost when the two plans cost the same is equal to 64 dollars.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |