document.write( "Question 1151827: A car slows down uniformly from a speed of 29.0 m/s to rest in 7.20 s. How far did it travel in that time? \n" ); document.write( "
Algebra.Com's Answer #773678 by ikleyn(52802)\"\" \"About 
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document.write( "There are several ways to get the answer.\r\n" );
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document.write( "1.  First calculate deceleration  a = \"29%2F7.2\" = 4.027778 m/s^2.\r\n" );
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document.write( "    Next calculate the distance  d = \"%28at%5E2%29%2F2\" = \"%284.02778%2A7.20%5E2%29%2F2\" = 104.4 meters.\r\n" );
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document.write( "2.  Or do the calculation, using average speed   \"V%5Baverage%5D\" = \"29.0%2F2\" = 14.5 m/s.\r\n" );
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document.write( "    Then the distance to the rest is  d = \"V%5Baverage%5D%2At\" = 14.5*7.20 = 104.4 meters  --- the same answer.\r\n" );
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