document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106350>Question 106350</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: There is a square and its area is 252. The square has 9 circles in it and you need to find the area of the circles added together. Could u show me how to do the problem please A.S.A.P. Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77362 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this equation: There is a square and its area is 252. The square has 9 circles in it and you need to find the area of the circles added together. Could u show me how to do the problem please A.S.A.P. Thank you<BR>\n" );
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document.write( "Each side of the square is sqrt252 = 15.8745...<BR>\n" );
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document.write( "Assuming the 9 circles are tightly packed in the square, the <BR>\n" );
document.write( "diameter of each circle is (1/3)sqrt252<BR>\n" );
document.write( "then each circle has radius = (1/2)[(1/3)sqrt252] = [sqrt(252)]/6<BR>\n" );
document.write( "Then the area of each circle is pi(radius)^2 = (252/36)pi = 7pi<BR>\n" );
document.write( "Then the area of all nine circles is 9*7pi = 63pi<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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