document.write( "Question 1151773: The following random sample was selected : 4, 6, 3, 5, 9, 3. Find the 95% confidence interval for the mean of the population. See Ex. 2 (Use your graphing calculator to find the mean and sample standard deviation.) \n" ); document.write( "
Algebra.Com's Answer #773618 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "mu = population mean \n" ); document.write( "sample = {4,6,3,5,9,3} \n" ); document.write( "n = 6 is the sample size\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use a calculator to find that \n" ); document.write( "xbar = 5 is the sample mean \n" ); document.write( "s = 2.280 is the approximate sample standard deviation\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 95% confidence, the critical z value is approximately z = 1.960 \n" ); document.write( "Use a table like this to find the proper critical value \n" ); document.write( "https://www.sjsu.edu/faculty/gerstman/StatPrimer/t-table.pdf \n" ); document.write( "(look at the value in the bottom row just above the 95% confidence level)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = lower boundary of confidence interval \n" ); document.write( "L = xbar - z*s/sqrt(n) \n" ); document.write( "L = 5 - 1.960*2.280/sqrt(6) \n" ); document.write( "L = 5 - 1.824 \n" ); document.write( "L = 3.176 \n" ); document.write( "L = 3.18\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "U = upper boundary of confidence interval \n" ); document.write( "U = xbar + z*s/sqrt(n) \n" ); document.write( "U = 5 + 1.960*2.280/sqrt(6) \n" ); document.write( "U = 5 + 1.824 \n" ); document.write( "U = 6.824 \n" ); document.write( "U = 6.82\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The 95% confidence interval is (L, U) = (3.18, 6.82) \n" ); document.write( "Which can also be expressed as 3.18 < mu < 6.82 \n" ); document.write( "The second version of the answer is in the form L < mu < U. \n" ); document.write( " \n" ); document.write( " |