document.write( "Question 1151760: The two right circular cones are similar. The height of the larger cone is 80 cm, and the area of its base is 3675 cm squared. The area of the base of the smaller cone is 147 Cm squared. What is the volume of the smaller cone? \n" ); document.write( "
Algebra.Com's Answer #773605 by MathLover1(20850)![]() ![]() You can put this solution on YOUR website! One dimensional measurements (side lengths, perimeters, etc.) are in the ratio \n" ); document.write( "\n" ); document.write( "Two dimensional measurements (area, surface area, etc.) are in the ratio of \n" ); document.write( "\n" ); document.write( "Three dimensional measurements (volume) are in the ratio of \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The ratio of the smaller area to the larger area is \n" ); document.write( "\n" ); document.write( "then. the ratio of the height of the smaller cone and height of the larger cone \n" ); document.write( " ( \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, ratio of the heights is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "then, volumes are in the ratio of \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using formula for the area of a smaller cone, we calculate radius: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using formula for the area of a larger cone, we calculate radius:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the volume of a smaller cone is: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the volume of a larger cone is: \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "check the ratio:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |