document.write( "Question 106347: Jo has 37coins( all nickels, dimes and quaters) worth $5.50. She has 4 more quatersthan nickels. How many dimes does Jo have? \n" ); document.write( "
Algebra.Com's Answer #77360 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Jo has 37coins( all nickels, dimes and quaters) worth $5.50. She has 4 more quarters than nickels. How many dimes does Jo have? \n" ); document.write( "----------------- \n" ); document.write( "Let number of nickels be \"x\" ; value of these is 5x cents \n" ); document.write( "Number of quarters is \"x+4\" ; value of these is 25(x+4)=25x+100 cents \n" ); document.write( "Number of dimes = 37-x-(x+4)=33-2x; value is 10(33-2x)=330-20x cents \n" ); document.write( "-------------------- \n" ); document.write( "EQUATION: \n" ); document.write( "value + value + value = 550 cents \n" ); document.write( "5x + 25x+100 + 330-20x = 550 \n" ); document.write( "10x = 120 \n" ); document.write( "x = 12 (number of nickels) \n" ); document.write( "x+4 = 16 (number of quarters) \n" ); document.write( "37-12-16=9 (number of dimes) \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |