document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151741>Question 1151741</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many kgs of tea at ₹13per kg must be mixed with 100 kg of tea at ₹17.50 per kg,so that a profit of 40% may be made by selling the mixture at ₹21 per kg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #773585 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=773585\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, find the cost price or x<BR>\n" );
document.write( "40% of x +x=21<BR>\n" );
document.write( "1.4x=21<BR>\n" );
document.write( "x=15  that is the cost to produce\r<BR>\n" );
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document.write( "y kg of tea at 13/kg<BR>\n" );
document.write( "100 kg of tea at 17.50/kg<BR>\n" );
document.write( "100+y kg of tea at 15/kg, cost price\r<BR>\n" );
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document.write( "so 13y+1750=(100+y)15=1500+15y<BR>\n" );
document.write( "-2y=-250<BR>\n" );
document.write( "y=125 kg of tea at 13/kg or 1625<BR>\n" );
document.write( "100kg of tea at 17.50 or 1750 \r<BR>\n" );
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document.write( "This is 225 kg costing 3375 or 15/kg </SPAN>\n" );
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