document.write( "Question 1151748: Amanda invests $25,000, part at 5% and the rest at 6%. The annual return on the 5% investment exceeds the annual return on the 6% investment by $40. How much did she invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #773577 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Amanda invests $ $\"25000\"$ \r
\n" ); document.write( "\n" ); document.write( "part $\"x\"$ at $\"5\"$ % and the rest $\"25000-x\"$ at $\"6\"$ %\r
\n" ); document.write( "\n" ); document.write( " The annual return on the $\"5\"$ %= $\"0.05\"$ investment exceeds the annual return on the $\"6\"$ %= $\"0.06\"$ investment by $ $\"40\"$ .\r
\n" ); document.write( "\n" ); document.write( "so, \r
\n" ); document.write( "\n" ); document.write( " $\"0.05x+=+0.06%2A%2825000+-+x%29+%2B+40\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"0.05x+=+1500+-+0.06x%2B+40\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"0.05x%2B+0.06x=+1540+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"0.11x=+1540+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=+1540%2F0.11+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=+14000+\"$ \r
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\n" ); document.write( "\n" ); document.write( "so, $\"14000\"$ is invested at $\"5\"$ % and $\"25000-14000=11000\"$ at $\"6\"$ %\r
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\n" ); document.write( "\n" ); document.write( "check interest difference: \r
\n" ); document.write( "\n" ); document.write( " $\"5\"$ %= $\"0.05\"$ of $\"14000\"$ is: $\"14000%2A0.05=700\"$
\n" ); document.write( " $\"6\"$ %= $\"0.06\"$ of $\"11000\"$ is: $\"11000%2A0.06=660\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"700-660=40\"$ -> which confirms our solution\r
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