document.write( "Question 1151683: Please help me to solve this question:
\n" ); document.write( "Assume that the random variable X is normally distributed, with mean=31.5 and standard deviation=1.4. Compute the probability P(X<28).
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Algebra.Com's Answer #773571 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
there are online calculators that allow you to solve this directly without having to figure out what the z-score is.
\n" ); document.write( "one such calculator can be found at https://www.omnicalculator.com/statistics/normal-distribution
\n" ); document.write( "i used this calculator and input a mean of 31.5 and a standard deviation of 1.4 and an X value of 28.
\n" ); document.write( "the calculator gave me p(X < 28), shown as p(x < X).
\n" ); document.write( "it also gave me p(X > 28), shown as p(x > X).
\n" ); document.write( "it also gave me the z-score, shown as -2.5.
\n" ); document.write( "here's what the output looked like.\r
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\n" ); document.write( "\n" ); document.write( "i also used another normal distribution calculator that gives you the result and also shows you a visualization of that looks like under the normal distribution curve.\r
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\n" ); document.write( "\n" ); document.write( "that calculator can be found at http://davidmlane.com/hyperstat/z_table.html\r
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\n" ); document.write( "\n" ); document.write( "with this calculator, you can enter z-score of -2.5 with a mean of 0 and a standard deviation of 1, or you can enter a raw score of 28 with a mean of 31.5 and a standard deviation of 1.4\r
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\n" ); document.write( "\n" ); document.write( "here's what the results from that calculator look like.\r
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\n" ); document.write( "\n" ); document.write( "note that the probability of getting a score < 28 using this calculator was slightly different than the probability using the omni calculator.
\n" ); document.write( "this will happen when using different calculator because they may not all have the same underlying assumptions regarding interpolation of results between known value and / or different assumption regarding intermediate rounding of results.
\n" ); document.write( "for practical purposes, probability estimates rounded from 2 to 4 decimal places should be all that you need.\r
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\n" ); document.write( "\n" ); document.write( "the omni calculator will give you the z-score if you give it the mean of 31.5 and an X value of 28 and a standard deviation of 1.4\r
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\n" ); document.write( "\n" ); document.write( "the david m. lane calculator will give you the result if you give it the mean of 31.5 and an X value of 28 and a standard deviation of 1.4, but it won't give you the z-score.\r
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\n" ); document.write( "\n" ); document.write( "to find the z-score, you would need to use the z-score formula.
\n" ); document.write( "that formula is z = (x - m) / s
\n" ); document.write( "z is the z-score
\n" ); document.write( "x is the raw score
\n" ); document.write( "m is the mean
\n" ); document.write( "s is the standard deviation, in this case.
\n" ); document.write( "using that formula, you would get:
\n" ); document.write( "z = (28 - 31.5) / 1.4
\n" ); document.write( "solve for z to get z = -2.5\r
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\n" ); document.write( "\n" ); document.write( "the omni calculator give me the same result that i get from using my TI-84 Plus calculator, with less effort.
\n" ); document.write( "bottom line:
\n" ); document.write( "omni is pretty good.
\n" ); document.write( "there is also an advance mode that can give you the probability between two values, either from 2 z-scores or from 2 raw scores.\r
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\n" ); document.write( "\n" ); document.write( "for your purposes, p(x < X) where X = 28 would be .0062 rounded to 4 decimal places.\r
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