document.write( "Question 1151680: ​Joe's annual income has been increasing each year by the same dollar amount. The first year his income was ​$19 comma 900​, and the 4th year his income was ​$23 comma 800. In which year was his income $ 31 comma 600 question mark \n" ); document.write( "
Algebra.Com's Answer #773549 by rfer(16322) ![]() You can put this solution on YOUR website! 23800-19900=3900 \n" ); document.write( "3900/3=1300 per yr increase \n" ); document.write( "31600-19900=11700 \n" ); document.write( "11700/1300=9th yr \n" ); document.write( "proof \n" ); document.write( "9*1300=11700 \n" ); document.write( "11700+19900=31600 \n" ); document.write( " |