document.write( "Question 1151690: A school planned to buy x Calculators for a total coast of Ksh 16200 . The supplier agreed to give a discount of Ksh 60 per calculator . The school was then able to get three extra calculators for the same amount of money .
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\n" ); document.write( " (2)Price of each calculator after the discount.\r
\n" ); document.write( "\n" ); document.write( " (b)Form an equation in x and hence determine the number of calculators the school bought.\r
\n" ); document.write( "\n" ); document.write( " (c) Calculate the discount offered to the school as a percentage.
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Algebra.Com's Answer #773531 by ikleyn(52788)\"\" \"About 
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document.write( "(a)  \r\n" );
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document.write( "    (1)   \"16200%2Fx\".\r\n" );
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document.write( "    (2)   \"16200%2F%28x%2B3%29\"\r\n" );
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document.write( "(b)       \"16200%2Fx\" - \"16200%2F%28x%2B3%29\" = 60.\r\n" );
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document.write( "          To solve it, first cancel the factor 60 in both side\r\n" );
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document.write( "              \"270%2Fx\" - \"270%2F%28x%2B3%29\" = 1\r\n" );
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document.write( "          Multiply both sides by x*(x+3)\r\n" );
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document.write( "               270*(x+3) - 270x = x*(x+3)\r\n" );
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document.write( "               x^2 + 3x - 810 = 0\r\n" );
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document.write( "               (x+30)*(x-27) = 0.\r\n" );
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document.write( "         Of the two roots  x= -30  and  x= 27, only positive x= 27 is the solution.\r\n" );
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document.write( "(c)      Thus the number of calculators before discount was 27, \r\n" );
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document.write( "             and the price for each single calculator was  \"16200%2F27\" = 600.\r\n" );
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document.write( "         After discount, the number of calculators  was  27+3 = 30, \r\n" );
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document.write( "             and the price for each single calculator was \"16200%2F30\" = 540.\r\n" );
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document.write( "         The discount from the price for each single calculator is  \"%28600-540%29%2F600\" = \"60%2F600\" = 0.1 = 10%.\r\n" );
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\n" ); document.write( "\n" ); document.write( "I answered all questions.\r
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