document.write( "Question 1151677: Information is given about a polynomial f left parenthesis x right parenthesis whose coefficients are real numbers. Find the remaining zeros of f.
\n" ); document.write( "Degree​ 4; ​ zeros: i, -13+1
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Algebra.Com's Answer #773501 by MathLover1(20850)\"\" \"About 
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Degree​ \"4\"; ​ => means there is \"4\" zeros\r
\n" ); document.write( "\n" ); document.write( "zeros: \"x%5B1%5D=i\", => complex zeros come in pairs, so you also have \"x%5B2%5D=-i\"\r
\n" ); document.write( "\n" ); document.write( "-13+1 ? I guess here are two zeros, \"13+\"and \"1\"\r
\n" ); document.write( "\n" ); document.write( "so, \"x%5B3%5D=13\", \"x%5B4%5D=1\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-x%5B1%5D%29%28x-x%5B2%5D%29%28x-x%5B3%5D%29%28x-x%5B4%5D%29\".....plug in given zeros\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-i%29%28x-%28-i%29%29%28x-13%29%28x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-i%29%28x%2Bi%29%28x-13%29%28x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2-i%5E2%29%28x-13%29%28x-1%29\"......since \"i%5E2=-1\", we have\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2-%28-1%29%29%28x-13%29%28x-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2%2B1%29%28x-13%29%28x-1%29\".......multiply all\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E4-14x%5E3+%2B14x%5E2+-14x+%2B+13\"\r
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