document.write( "Question 1151621: xavier and yolanda have been married for exactly 40 years. yolanda is four years older than xavier now the sum of their ages is 126 how old was yolanda when they were married \n" ); document.write( "

Algebra.Com's Answer #773428 by ikleyn(52795) $\"\"$ $\"About$

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document.write( "Let X be Xavier age and Y be Yolanda age (thanks for giving them appropriate names (!) )\r\n" );
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document.write( "Then\r\n" );
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document.write( "    Y + X = 126\r\n" );
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document.write( "    Y - X =   4\r\n" );
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document.write( "Add equations. You will find  Y =  = 65.\r\n" );
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document.write( "So, Yolanda is 65 years old now.\r\n" );
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document.write( "40 years ago, when they were married, Yolanda was 65-40 = 25 years old.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved.\r
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\n" ); document.write( "\n" ); document.write( "Nice problem --- thanks for posting it (!)\r
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