document.write( "Question 1151615: Kwame’s age is six(6) times that of his brother. In Ten(10) years time, kwame will be four times as old his brother. What are their present ages.?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #773421 by ikleyn(52799)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the brother's age now.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then the Kwame's age is 6x years.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In 10 years\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 4*(x+10) = 6x + 10.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve for x\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 4x + 40 = 6x + 10\r\n" ); document.write( "\r\n" ); document.write( " 40 - 10 = 6x - 4x\r\n" ); document.write( "\r\n" ); document.write( " 30 = 2x\r\n" ); document.write( "\r\n" ); document.write( " x = 30/2 = 15.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. Their present ages are 15 and 90 years.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " If you tell me that it is impossible, I will answer you that it may happen in parallel Universe.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |