document.write( "Question 1151556: Prove or disprove: cos^6(x)=-2+3cos^2(x)+3sin^4(x)-sin^6(x)
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Algebra.Com's Answer #773346 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
\"cos%5E6%28x%29=-2%2B3cos%5E2%28x%29%2B3sin%5E4%28x%29-sin%5E6%28x%29\"\r\n" );
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document.write( "\"%28cos%5E2%28x%29%5E%22%22%29%5E3=-2%2B3cos%5E2%28x%29%2B3sin%5E4%28x%29-sin%5E6%28x%29\"\r\n" );
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document.write( "Substitute 1-sin²(x) for cos²(x)\r\n" );
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document.write( "To uncomplicate matters, let y = sin²(x)\r\n" );
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document.write( "\"%281-y%5E%22%22%29%5E3=-2%2B3%281-y%5E%22%22%29%2B3%28y%5E%22%22%29%5E2-%28y%5E%22%22%29%5E3\"\r\n" );
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document.write( "Simplify\r\n" );
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document.write( "\"1-3y%2B3y%5E2%2By%5E3=-2%2B3-3y%2B3y%5E2-y%5E3\"\r\n" );
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document.write( "Simplify further\r\n" );
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document.write( "\"1-3y%2B3y%5E2-y%5E3=1-3y%2B3y%5E2-y%5E3\"\r\n" );
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document.write( "Both sides are identical, so the problem is proved.\r\n" );
document.write( "It's OK to work with both sides of an identity as long\r\n" );
document.write( "as you don't change the value of either side, by adding,\r\n" );
document.write( "subtracting, multiplying, or dividing to, from, or by both\r\n" );
document.write( "sides.\r\n" );
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document.write( "Edwin

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