document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151537>Question 1151537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 4% salt solution is mixed with a 16% salt solution to obtain 600ml of 10% salt solution. How much of the 4% salt solution was used<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #773312 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=773312\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of ml of the 4% salt solution.<BR>\n" );
document.write( "y = number of ml of the 16% salt solution.<BR>\n" );
document.write( "you get two equations that need to be solved simultaneously.<BR>\n" );
document.write( "they are:<BR>\n" );
document.write( "x + y = 600<BR>\n" );
document.write( ".04 * x + .16 * y = .10 * 600<BR>\n" );
document.write( "the first equation gets yu the total milliliters used.<BR>\n" );
document.write( "the second equation gets you the total amount of salt in the mixture.\r<BR>\n" );
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document.write( "simplify the equations to get:<BR>\n" );
document.write( "x + y = 600<BR>\n" );
document.write( ".04 * x + .16 * y = 60\r<BR>\n" );
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document.write( "multiply both sides of the first equation by .04 and leave the second equation as is to get:<BR>\n" );
document.write( ".04 * x + .04 * y = 24<BR>\n" );
document.write( ".04 * x + .16 * y = 60\r<BR>\n" );
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document.write( "subtract the first equation from the second to get:<BR>\n" );
document.write( ".12 * y = 36<BR>\n" );
document.write( "solve for y to get:<BR>\n" );
document.write( "y = 36 /.12 = 300\r<BR>\n" );
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document.write( "since x = y = 600, then x must be equal to 300.\r<BR>\n" );
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document.write( "you have x = 300 and y = 300<BR>\n" );
document.write( "you also have .04 * 300 + .16 * 300 = 12 + 48 = 60\r<BR>\n" );
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document.write( "both equations are true when x = 300 and y = 300\r<BR>\n" );
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document.write( "first equation is x + y = 600 which becomes 300 + 300 = 600 which is true.<BR>\n" );
document.write( "second equation becomes .04 * 300 + .16 * 300 = .10 * 600 which becomes 12 + 48 = 60 which is also true.\r<BR>\n" );
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document.write( "your solution is that 300 milliliters of the 4% solution was used.\r<BR>\n" );
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