document.write( "Question 1151486: the perimeter of a rectangle parking lot is 320m.If the length of the parking lot is 95m,what is the width?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #773250 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "P = 2*(L+W) is the perimeter of a rectangle with length L and width W
\n" ); document.write( "L = 95 and W is unknown. P = 320 is the given perimeter\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "2(L+W) = P
\n" ); document.write( "2(95+W) = 320 .... plug in P = 320 and L = 95
\n" ); document.write( "2(95+W)/2 = 320/2 .... divide both sides by 2
\n" ); document.write( "95+W = 160
\n" ); document.write( "W+95 = 160
\n" ); document.write( "W+95-95 = 160-95 ... subtract 95 from both sides
\n" ); document.write( "W = 65\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Answer: The width is 65 meters\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( "P = 2(95+65)
\n" ); document.write( "P = 2(160)
\n" ); document.write( "P = 320
\n" ); document.write( "We get the proper perimeter, so the answer is confirmed.
\n" ); document.write( " \n" ); document.write( "
\n" );