document.write( "Question 1151474: A man's age is 6 less than three times his son's age.the sum of their age is 58.how old is the man's age? \n" ); document.write( "
Algebra.Com's Answer #773222 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let man's age be \"x\" and his son's age \"y\"\r
\n" ); document.write( "\n" ); document.write( "if a man's age is \"6\" less than \"three\"\"+times\" his son's age. we have\r
\n" ); document.write( "\n" ); document.write( "\"x=3y-6\".........eq.1\r
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\n" ); document.write( "\n" ); document.write( "if the sum of their age is \"58\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=58\"........eq.2\r
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\n" ); document.write( "\n" ); document.write( "substitute \"x\" from eq.1\r
\n" ); document.write( "\n" ); document.write( "\"3y-6%2By=58\"........eq.2.....solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"4y=58%2B6\"\r
\n" ); document.write( "\n" ); document.write( "\"4y=64\"\r
\n" ); document.write( "\n" ); document.write( "\"y=64%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=16\"\r
\n" ); document.write( "\n" ); document.write( "now calculate \"x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2A16-6\".........eq.1\r
\n" ); document.write( "\n" ); document.write( "\"x=42\"\r
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\n" ); document.write( "\n" ); document.write( " the man is \"42\" years old\r
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