document.write( "Question 106202: Find three consecutive odd integers such that the largest increased by three times the second is 47 less than the smallest. \n" ); document.write( "

Algebra.Com's Answer #77322 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Just write equation for what it says:
\n" ); document.write( ":
\n" ); document.write( "\"Find three consecutive odd integers\"
\n" ); document.write( "x, x+2, x+4
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\n" ); document.write( "\"the largest increased by three times the second is 47 less than the smallest.\"
\n" ); document.write( "(x+4) + 3(x+2) = x - 47
\n" ); document.write( "x + 4 + 3x + 6 = x - 47
\n" ); document.write( "4x + 10 = x - 47
\n" ); document.write( "4x -x = -47 - 10
\n" ); document.write( "3x = - 57
\n" ); document.write( "x = -57/3
\n" ); document.write( "x = -19
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\n" ); document.write( "Our three odd integers: -19, -17, -15:
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\n" ); document.write( "Check solution in the statement,:
\n" ); document.write( "\"the largest increased by three times the second is 47 less than the smallest.\"
\n" ); document.write( "-15 + 3(-17) = -19 - 47
\n" ); document.write( "-15 - 51 = -19 - 47
\n" ); document.write( " \n" ); document.write( "

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