document.write( "Question 1151458: A pharmacist has 6 liters of an 8% boric acid solution. How much water should he add to dilute the solution to a 5% boric acid solution? \n" ); document.write( "
Algebra.Com's Answer #773203 by Edwin McCravy(20054)\"\" \"About 
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document.write( "He starts with 6 liters of an 8% boric acid solution.\r\n" );
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document.write( "8% of 6 is 0.48, so those 6 liters of liquid contains just 0.48 liters of pure\r\n" );
document.write( "boric acid and the rest is water.\r\n" );
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document.write( "Now he adds x liters of water and now he has 6+x liters of liquid.\r\n" );
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document.write( "That 6+x liters of liquid still contains just 0.48 liters of pure boric acid.\r\n" );
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document.write( "That 0.48 liters of pure boric acid is now only 5% of those 6+x liters of liquid.\r\n" );
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document.write( "So 0.48 = 5% of 6+x\r\n" );
document.write( "   0.48 = 0.05(6+x)\r\n" );
document.write( "     48 = 5(6+x)\r\n" );
document.write( "     48 = 30+5x\r\n" );
document.write( "     18 = 5x\r\n" );
document.write( "    3.6 = x\r\n" );
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document.write( "Answer: He needs to add 3.6 liters of water.\r\n" );
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document.write( "Edwin
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