document.write( "Question 106109: at noon, a passenger ship and a freighter left a port traveling in oposite directions. By midnight, the passanger ship was 3 times farther from port than the freighter was. How far was the freighter from port if the distance between the ships was 84 miles? \n" ); document.write( "

Algebra.Com's Answer #77320 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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at noon, a passenger ship and a freighter left a port traveling in opposite directions. By midnight, the passenger ship was 3 times farther from port than the freighter was. How far was the freighter from port if the distance between the ships was 84 miles?
\n" ); document.write( ":
\n" ); document.write( "Let x = freighters distance from the port
\n" ); document.write( "Then
\n" ); document.write( "3x = pass ship from port
\n" ); document.write( ":
\n" ); document.write( "3x + x = 84
\n" ); document.write( "4x = 84
\n" ); document.write( "x = 84/4
\n" ); document.write( "x = 21 mi from port, a real slow ship
\n" ); document.write( ":
\n" ); document.write( "Freighter----x--------Port-------------------3x------------------Pass \n" ); document.write( "

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