document.write( "Question 1151454: A solution containing a 9% concentration of acid is mixed with a solution containing a 5% concentration of acid to get 100mL of solution containing an 8% concentration of acid. How many mL of each solution is needed? \n" ); document.write( "
Algebra.Com's Answer #773196 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let's say we had two bottles of the acid.
\n" ); document.write( "Bottle A has 9% concentration of acid.
\n" ); document.write( "Bottle B has 5% concentration of acid.\r
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\n" ); document.write( "\n" ); document.write( "We don't know how many mL of solution is in each bottle, so let,
\n" ); document.write( "x = amount of solution in bottle A
\n" ); document.write( "y = amount of solution in bottle B
\n" ); document.write( "Each bottle contains pure acid plus other stuff (either water only or other chemicals as well).\r
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\n" ); document.write( "\n" ); document.write( "We want to mix the two bottles (A and B) so that we end up with 100 mL of total solution.
\n" ); document.write( "This means the amounts x and y must add to 100
\n" ); document.write( "x+y = 100\r
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\n" ); document.write( "\n" ); document.write( "Solve for y to get
\n" ); document.write( "x+y = 100
\n" ); document.write( "x+y-x = 100-x
\n" ); document.write( "y = 100-x
\n" ); document.write( "We will use this equation later. \r
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\n" ); document.write( "\n" ); document.write( "From bottle A, we have 9% acid concentration. If we have x mL of solution in this bottle, then there is 0.09*x mL of pure acid here. \r
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\n" ); document.write( "\n" ); document.write( "Inside bottle B is 0.05*y mL of pure acid because of the 5% concentration.\r
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\n" ); document.write( "\n" ); document.write( "All together, there is 0.09x+0.05y mL of pure acid. Let's call this quantity C. So C = 0.09x+0.05y\r
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\n" ); document.write( "\n" ); document.write( "We want to divide the value of C over 100 which was the total amount of solution we end up with when we mix the two bottles. \r
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\n" ); document.write( "\n" ); document.write( "The expression C/100 is the percentage of pure acid in the final mixture.
\n" ); document.write( "We want this percentage to be 8%\r
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\n" ); document.write( "\n" ); document.write( "So,
\n" ); document.write( "C/100 = 0.08
\n" ); document.write( "C = 100*0.08 ...... multiply both sides by 100
\n" ); document.write( "C = 8
\n" ); document.write( "0.09x+0.05y = 8 .... replace C with 0.09x+0.05y
\n" ); document.write( "0.09x+0.05( y ) = 8
\n" ); document.write( "0.09x+0.05( 100-x ) = 8 .... plug in y = 100-x
\n" ); document.write( "0.09x+0.05(100)+0.05(-x) = 8 .... distribute
\n" ); document.write( "0.09x+5-0.05x = 8
\n" ); document.write( "0.04x+5 = 8
\n" ); document.write( "0.04x+5-5 = 8-5 ..... subtract 5 from both sides
\n" ); document.write( "0.04x = 3
\n" ); document.write( "0.04x/0.04 = 3/0.04 .... divide both sides by 0.04
\n" ); document.write( "x = 75
\n" ); document.write( "We will need 75 mL of the 9% concentration\r
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\n" ); document.write( "\n" ); document.write( "y = 100-x
\n" ); document.write( "y = 100-75 .... plug in x = 75
\n" ); document.write( "y = 25
\n" ); document.write( "and we need 25 mL of the 5% concentration.\r
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\n" ); document.write( "\n" ); document.write( "Answers:
\n" ); document.write( "75 mL of the 9% concentration
\n" ); document.write( "25 mL of the 5% concentration\r
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\n" ); document.write( "\n" ); document.write( "As a check,
\n" ); document.write( "9% of 75 = 0.09*75 = 6.75 is the amount of pure acid from bottle A
\n" ); document.write( "5% of 25 = 0.05*25 = 1.25 is the amount of pure acid from bottle B
\n" ); document.write( "6.75+1.25 = 8 mL is the amount of pure acid in total after mixing both bottles
\n" ); document.write( "100 mL is the total amount of solution
\n" ); document.write( "8/100 = 0.08 = 8% is the proper concentration we're aiming for.
\n" ); document.write( "This helps confirm the answer
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