document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106100>Question 106100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has legs 15 inches and 12 inches. Every dimension is multiplied by 1/3 to form a new right triangle with legs 5 inches and 4 inches.  How is the ratio of the areas related to the ratio of corresponding sides? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77319 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A right triangle has legs 15 inches and 12 inches. Every dimension is multiplied by 1/3 to form a new right triangle with legs 5 inches and 4 inches. How is the ratio of the areas related to the ratio of corresponding sides?<BR>\n" );
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document.write( "Find the area of both triangles and see:<BR>\n" );
document.write( "A1 = .5*15*12<BR>\n" );
document.write( "A1 = 90 sq/in<BR>\n" );
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document.write( "A2 = .5*5*4<BR>\n" );
document.write( "A2 = 10 sq/in<BR>\n" );
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document.write( "It looks like it's 9:1 ratio.<BR>\n" );
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document.write( "1/3 of both sides = 1/9 the area </SPAN>\n" );
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