document.write( "Question 1151415: $10,000 is invested, part at 4% and the rest at 5% interest. The annual interest from the 4% investment is $40 more than that from the 5% investment. Find the amounts at 4% and 5%\r
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Algebra.Com's Answer #773152 by MathLover1(20855)\"\" \"About 
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$\"10000+\"is invested, part at \"4\"% and the rest \"x\" at \"5\"% interest. \r
\n" ); document.write( "\n" ); document.write( "Let\r
\n" ); document.write( "\n" ); document.write( "\"x\" = amount in dollars invested at \"4\" %\r
\n" ); document.write( "\n" ); document.write( "\"y\" = amount in dollars invested at \"5\" %\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=10000\"\r
\n" ); document.write( "\n" ); document.write( "\"y=10000-x\"......eq.1\r
\n" ); document.write( "\n" ); document.write( "Convert above information into income.\r
\n" ); document.write( "\n" ); document.write( " \"I=+P%2AR%2AT\" (Interest = Principal * Rate* Time)\r
\n" ); document.write( "\n" ); document.write( "If you put\"+x\" in the bank at \"4\" %=\"0.04\", your interest would be \"0.04x\"
\n" ); document.write( "and \"%2810000-x%29+\" at \"5\" %=\"0.05\", your interest earned from \"5\"% would be \"0.05%2810000-x%29+\"\r
\n" ); document.write( "\n" ); document.write( "if the annual interest from the \"4\"% investment is $\"40\" more than that from the \"5\"% investment, we have\r
\n" ); document.write( "\n" ); document.write( " \"0.04x=0.05%2810000-x%29%2B40\"\r
\n" ); document.write( "\n" ); document.write( "\"0.04x=500-0.05x%2B40\"\r
\n" ); document.write( "\n" ); document.write( "\"0.04x%2B0.05x=500%2B40\"\r
\n" ); document.write( "\n" ); document.write( "\"0.09x=540\"\r
\n" ); document.write( "\n" ); document.write( "\"x=540%2F0.09\"\r
\n" ); document.write( "\n" ); document.write( "\"x=6000\"\r
\n" ); document.write( "\n" ); document.write( "‭now find \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=10000-6000\" ......eq.1\r
\n" ); document.write( "\n" ); document.write( "\"y=4000\" \r
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\n" ); document.write( "\n" ); document.write( "So, $\"6000\" was invested ‬at \"4\"% and $\"4000\" at \"5\"% \r
\n" ); document.write( "\n" ); document.write( "check annual interest:\r
\n" ); document.write( "\n" ); document.write( "$ \"6000%2A0.04=240\" \r
\n" ); document.write( "\n" ); document.write( "$ \"4000%2A0.05=200\" =>difference is $ \"40\"\r
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