document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151327>Question 1151327</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A  company is  going to have a  dinner party  in a restaurant  for its  top employees . The restaurant is going to  charge them $ 280 for the use  of their  function room, plus  40 per  dinner. The company  has a budget of  no more than $ 1500. What is the  greatest number of  people they can invite to  this dinner? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #773048 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=773048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the constant is 280 and the cost is 40x, where x is number of people.<BR>\n" );
document.write( "40x+280 <1500<BR>\n" );
document.write( "40x<1220<BR>\n" );
document.write( "x<31 people or 30 people maximum </SPAN>\n" );
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