document.write( "Question 1151297: A smartphone company found in a survey that 17% of people did not own a smartphone, 18% owned a smartphone only, 29% owned a smartphone and only a tablet, 21% owned a smartphone and only a computer, and 15% owned all three. If a person were selected at random, what is the probability that the person would own a smartphone only or a smartphone and computer only? \n" ); document.write( "
Algebra.Com's Answer #773026 by ikleyn(52780)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            Honestly, I don't know and don't understand  WHY  the respectful tutor Jim chose this complicated way to solve the problem.\r
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\n" ); document.write( "\n" ); document.write( "            It can be solved in  MUCH  SIMPLER  way,  and I will show it to you now.\r
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\n" ); document.write( "\n" ); document.write( "You have the universal set of all people surveyed.\r
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\n" ); document.write( "\n" ); document.write( "        Notice that  17% + 18% + 29% + 21% + 15% = 100%,  so these subsets cover the entire set.\r
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\n" ); document.write( "\n" ); document.write( "Now,  from the text,  it should be clear to you that all listed categories of people are  DISJOINT :
\n" ); document.write( "the intersections between any two different categories are  EMPTY.\r
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\n" ); document.write( "\n" ); document.write( "        It is clear and obvious from the definitions of these categories in the post.\r
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\n" ); document.write( "\n" ); document.write( "Now,  the question is :   what is the probability to randomly select from the union of the  {18%}  and  {21%}  subsets.\r
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\n" ); document.write( "\n" ); document.write( "But of course,  this probability is the sum  18% + 21% = 39%.          ANSWER\r
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\n" ); document.write( "\n" ); document.write( "It is a  DIRECT  CONSEQUENCE  that the given categories \r
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document.write( "    a)  cover the entire universal set,     and that\r\n" );
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document.write( "    b)  the categories are disjoint, i.e. have empty intersections.\r\n" );
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\n" ); document.write( "\n" ); document.write( "It is fully consistent with the general formula of the Elementary probability theory\r
\n" ); document.write( "\n" ); document.write( "         P(A U B) = P(A) + P(B) \r
\n" ); document.write( "\n" ); document.write( "for the disjoint events.\r
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\n" ); document.write( "\n" ); document.write( "My solution is  completed  at this point.\r
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\n" ); document.write( "\n" ); document.write( "A good style educational / (teaching)  tradition assumes and requires that used teaching tools should not
\n" ); document.write( "be more complicated than the problem itself.\r
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\n" ); document.write( "\n" ); document.write( "Or,  in other words,  the solution should be  AS  SIMPLE  AS  POSSIBLE   //   still remaining to be correct.\r
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