document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151286>Question 1151286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve this application problem using a system of equations: In a basketball game, Alan scored 30 points, consisting only of three-point shots and two-point shots. He made a total of 11 shots. How many shots of each type did he make?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772967 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772967\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = number of 2 point shots.<BR>\n" );
document.write( "y = number of 3 point shots.<BR>\n" );
document.write( "x + y = 11<BR>\n" );
document.write( "2x + 3y = 30<BR>\n" );
document.write( "multiply both sides of first equation by 2 and leave second equation alone to get:<BR>\n" );
document.write( "2x + 2y = 22<BR>\n" );
document.write( "2x + 3y = 30<BR>\n" );
document.write( "subtract first equation from second to get:<BR>\n" );
document.write( "y = 8<BR>\n" );
document.write( "since x + y = 11, then x = 3<BR>\n" );
document.write( "with x = 3 and y = 8, you get:<BR>\n" );
document.write( "x + y = 3 + 8 = 11<BR>\n" );
document.write( "2x + 3y = 6 + 24 = 30<BR>\n" );
document.write( "solution is number of 2 point shots is 3 and number of 3 point shots is 8.\r<BR>\n" );
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