document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151235>Question 1151235</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of 40% alcohol solution must be mixed with 70% solution to obtain 30 gallons of 52% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772918 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a very different way for solving problems like this involving a mixture of two ingredients.<br><BR>\n" );
document.write( "If you understand it, it will get you to the answer much faster, and with less effort, than the traditional algebraic method.<br><BR>\n" );
document.write( "(1) 52% is 2/5 of the way from 40% to 70%.  (40 to 70 is 30; 40 to 52 is 12; 12/30 = 2/5)<br><BR>\n" );
document.write( "(2) That means 2/5 of the mixture is the 70% ingredient.<br><BR>\n" );
document.write( "ANSWER:<BR>\n" );
document.write( "2/5 of 30 gallons, or 12 gallons, of the 70% solution;<BR>\n" );
document.write( "3/5 of 30 gallons, or 18 gallons, of the 40% solution.<br><BR>\n" );
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