document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106246>Question 106246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> john is x years old. his father is 3 times as old as he is. his mother is 3 years younger than his father. find the sum of their ages in terms of x in 10 years time. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77291 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> NOW:<BR>\n" );
document.write( "x=John's age<BR>\n" );
document.write( "3x=father's age<BR>\n" );
document.write( "3x-3=mother's age\r<BR>\n" );
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document.write( "TEN YEARS FROM NOW:<BR>\n" );
document.write( "x+10=John's age<BR>\n" );
document.write( "3x+10=father's age<BR>\n" );
document.write( "(3x-3)+10=mother's age\r<BR>\n" );
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document.write( "SO THE SUM OF THEIR AGES IN TEN YEARS TIME IS:\r<BR>\n" );
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document.write( "x+10+3x+10+(3x-3)+10  get rid of parens\r<BR>\n" );
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document.write( "x+10+3x+10+3x-3+10  collect like terms\r<BR>\n" );
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document.write( "7x+27---------------ans\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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