document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1151211>Question 1151211</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 45 in squared . Find the lengths of the sides of the two squares. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #772894 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=772894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A quick mental solution doesn't require any algebra.<br><BR>\n" );
document.write( "The sum of the areas is a whole number; the difference in the side lengths is a whole number.  That virtually assures that both side lengths are whole numbers.<br><BR>\n" );
document.write( "The sum of the areas is a small number; so solve using (organized) trial and error....<br><BR>\n" );
document.write( "(1)^2 + (1+3)^2 = 1+16 = 17  nope...<BR>\n" );
document.write( "(2)^2+(2+3)^2 = 4+25 = 29  nope...<BR>\n" );
document.write( "(3)^2+(3+3)^2 = 9+36 = 45  YES!!<br><BR>\n" );
document.write( "ANSWER: The side lengths ar 3 and 6.<br><BR>\n" );
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