document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106238>Question 106238</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 5 gallon radiator containing a mixture of water and antifreeze was supposed to contain a 50% antifreeze solution. When tested, it was found to have only 40% antifreeze. How much must be drained out and replaced with pure antifreeze so that the radiator will contain the desired 50% antifreeze.\r<BR>\n" );
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document.write( "thank u for sparing time for my problem...thanks.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77288 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77288\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount that needs to be drained and replaced with pure antifreeze\r<BR>\n" );
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document.write( "Now we know that the amount of pure antifreeze left after we drain x amount out (0.40(5-x))plus the amount of pure antifreeze added (x) has to equal the amount of pure antifreeze in the final mixture (0.50*5).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.40(5-x)+x=0.50*5  get rid of parens and simplify\r<BR>\n" );
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document.write( "2-0.40x+x=2.5  subtract 2 from both sides\r<BR>\n" );
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document.write( "2-2-0.40x+x=2.5-2  collect like terms\r<BR>\n" );
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document.write( "0.60x=0.5  divide both sides by 0.60\r<BR>\n" );
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document.write( "x=0.833333--  gal----------amount that needs to be drained and replaced with pure antifreeze\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "0.40(5-0.83333333333)+0.8333333333333=2.5\r<BR>\n" );
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document.write( "1.666666666666+0.8333333333333333333=2.5<BR>\n" );
document.write( "~2.5=2.5\r<BR>\n" );
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document.write( "Hope this helps----ptaylor </SPAN>\n" );
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