document.write( "Question 1151143: In the diagram to the bottom, ABCD and DEFG are congruent squares. Find the measure of angle DHG. \r
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Algebra.Com's Answer #772814 by ikleyn(52863) $\"\"$ $\"About$

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document.write( "From the condition, segment DG is congruent to segment DC.\r\n" );
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document.write( "So the triangle DGC is isosceles.\r\n" );
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document.write( "The angle GDC of this triangle is  60° + 90° = 150°.\r\n" );
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document.write( "Therefore, the two angles  DGC  and  DCG  are congruent as the base angles of the isosceles triangle GDC\r\n" );
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document.write( "and have measure   = 15°  each.\r\n" );
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document.write( "Then the angle DHG is the complement of the angle DGH, since these angles are the acute angles in the right angled triangle DHG.\r\n" );
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document.write( "Thus the angle DHG  is  75°.      ANSWER\r\n" );
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