document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15532>Question 15532</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I submitted this problem Friday evening and I got no response. I need to know if I'm right or wrong, it's due tomorrow.<BR>\n" );
document.write( "If 10 cards are drawn without replacement from an ordinary deck, find the probability of obtaining exactly 3 aces or exactly 3 kings (or both). I tried<BR>\n" );
document.write( "using (52 choose 10) for the denominator and (10 choose 3)^4 for the numerator(4 for each suite). It seems as though I'm missing something. Please help asap.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7728 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "If 10 cards are drawn without replacement from an ordinary deck, find the probability of obtaining exactly 3 aces or exactly 3 kings (or both). I tried<BR>\n" );
document.write( "using (52 choose 10) for the denominator and (10 choose 3)^4 for the numerator(4 for each suite). It seems as though I'm missing something. Please help asap.<BR>\n" );
document.write( "Total number of possibilities. N = ...taking 10 out of 52 cards = 52C10<BR>\n" );
document.write( " number of successes....M =...taking 3 aces and rest seven other than aces.<BR>\n" );
document.write( "   taking 3 aces out of 4 aces ..=4C3<BR>\n" );
document.write( "   taking 7 cards out of rest other than aces...=48C7<BR>\n" );
document.write( "   M = 4C3 * 48C7 <BR>\n" );
document.write( "  probability = M/N = 4C3 * 48C7 /52C10 = (4*48*47*46*45*44*43*42)*(10*9*8*7*6*5*4*3*2*1)/(7*6*5*4*3*2*1)*(52*51*50*49*48*47*46*45*44*43)<BR>\n" );
document.write( "   FOr 3 kings only the answer is same <BR>\n" );
document.write( "for both 3 kings and 3 aces you can try your self on the above basis </SPAN>\n" );
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