document.write( "Question 1151136: Three numbers are in an arithmetic progression with a common difference of 6. If 4 is subtracted from the first number, 1 is subtracted from the second number, and the third number is first decreased by 3 and then multiplied by 3, then the resulting three numbers form a geometric progression. Find the original three numbers. \n" ); document.write( "
Algebra.Com's Answer #772771 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let the original three numbers be x-6, x, and x+6. \n" ); document.write( "Then (x-6)-4 = x-10, x-1, and 3((x+6)-3) = 3x+9 form a geometric progression, which means there is a common ratio between the terms. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Both solutions satisfy the conditions of the problem. \n" ); document.write( "(A) x = -7/2: \n" ); document.write( "The original arithmetic progression is \n" ); document.write( "-19/2, -7/2, 5/2 \n" ); document.write( "When 4 is subtracted from the first term, 1 is subtracted from the second term, and the third term is decreased by 3 and then multiplied by 3, the resulting numbers form a geometric progression: \n" ); document.write( "-27/2, -9/2, -3/2 \n" ); document.write( "(B) x = 13: \n" ); document.write( "The original arithmetic progression is \n" ); document.write( "7, 13, 19 \n" ); document.write( "When 4 is subtracted from the first term, 1 is subtracted from the second term, and the third term is decreased by 3 and then multiplied by 3, the resulting numbers form a geometric progression: \n" ); document.write( "3, 12, 48 \n" ); document.write( " \n" ); document.write( " |