document.write( "Question 1151132: Fame is 10 yrs. older than EJ. Five years ago, EJ was two years more than one fourth as old as Fame. what are their present age?\r
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Algebra.Com's Answer #772768 by ikleyn(52802) $\"\"$ $\"About$

You can put this solution on YOUR website!
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document.write( "Let x be the EJ age;   then Fame's age is (x+10) years.\r\n" );
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document.write( "Five years ago:  EJ age is (x-5) years;  Fame's age is ((x+10)-5) = (x+5) years.\r\n" );
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document.write( "The basic equation is\r\n" );
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document.write( "    x-5 = 2 + .\r\n" );
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document.write( "Multiply both sides by 4\r\n" );
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document.write( "    4x - 20 = 8 + (x+5).\r\n" );
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document.write( "Simplify and solve for x\r\n" );
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document.write( "    4x - x = 8 + 5 + 20\r\n" );
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document.write( "    3x     = 33\r\n" );
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document.write( "     x     = 33/3 = 11.\r\n" );
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document.write( "ANSWER.  EJ's present age is 11 years.  Fame's present age is  21 years.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Ignore the \"solution\" by @josgarithmetic, since it is WRONG.\r
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