document.write( "Question 1151128: Which has greater volume
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Algebra.Com's Answer #772762 by MathLover1(20849)\"\" \"About 
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Rolling the cylinder lengthwise means that the circumference of the cylinder becomes the magnitude of the \"width=W\", and the height is the magnitude of the \"length=L\"\r
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\n" ); document.write( "\n" ); document.write( "so, if the circumference of the cylinder is \"2pi%2Ar+=+W\"\r
\n" ); document.write( "\n" ); document.write( "\"r+=+W%2F%282pi%29\"\r
\n" ); document.write( "\n" ); document.write( "Then the volume is:\r
\n" ); document.write( "\n" ); document.write( "\"V%5B1%5D+=+pi%2Ar%5E2%2AL\"\r
\n" ); document.write( "\n" ); document.write( "\"V%5B1%5D+=+pi%28W%2F%282pi%29%29%5E2%2AL\"\r
\n" ); document.write( "\n" ); document.write( "\"V+%5B1%5D=+pi%28W%5E2%2F%284%2Api%5E2%29%29L\"\r
\n" ); document.write( "\n" ); document.write( "\"V%5B1%5D+=+%281%2F%284pi%29%29W%5E2%2AL\"\r
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\n" ); document.write( "\n" ); document.write( "if the circumference of the cylinder is\"2pi%2Ar+=+L\"\r
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\n" ); document.write( "\n" ); document.write( "\"r+=+L%2F%282pi%29\"\r
\n" ); document.write( "\n" ); document.write( "Then the volume is:\r
\n" ); document.write( "\n" ); document.write( "\"V%5B2%5D+=+pi%2Ar%5E2%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"V%5B2%5D+=+pi%28L%2F%282pi%29%29%5E2%2AW\"\r
\n" ); document.write( "\n" ); document.write( "\"V+%5B2%5D=+pi%28L%5E2%2F%284%2Api%5E2%29%29W\"\r
\n" ); document.write( "\n" ); document.write( "\"V%5B2%5D+=+%281%2F%284pi%29%29L%5E2%2AW\"\r
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\n" ); document.write( "\n" ); document.write( "Dividing the width folding by the length folding:\r
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\n" ); document.write( "\n" ); document.write( "Thus the ratio of the two volumes is the ratio of the length to the width (interesting.) So the width folding has greater volume.\r
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