document.write( "Question 106173This question is from textbook Texas Algebra I
\n" ); document.write( ": The length of a rectangle is 3 Inches more than its width. The perimeter of the rectangle is 30 inches. \n" ); document.write( "
Algebra.Com's Answer #77275 by HyperBrain(694)\"\" \"About 
You can put this solution on YOUR website!
Let x=length
\n" ); document.write( "____y=width
\n" ); document.write( "____2(x+y)=perimeter\r
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\n" ); document.write( "\n" ); document.write( "IF The length of a rectangle is 3 Inches more than its width, then,\r
\n" ); document.write( "\n" ); document.write( "\"x=y%2B3\"\r
\n" ); document.write( "\n" ); document.write( "IF The perimeter of the rectangle is 30 inches, then,\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%2By%29=30\"\r
\n" ); document.write( "\n" ); document.write( "Solving \"2%28x%2By%29=30\",\r
\n" ); document.write( "\n" ); document.write( "\"2%28x%2By%29=30\"
\n" ); document.write( "\"%282%28x%2By%29%29%2F%282%29=30%2F2\"
\n" ); document.write( "\"x%2By=15\"\r
\n" ); document.write( "\n" ); document.write( "But, \"x=y%2B3\", thus,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"y%2B3%2By=15\"
\n" ); document.write( "\"y%2By%2B3=15\"
\n" ); document.write( "\"2y%2B3=15\"
\n" ); document.write( "\"2y%2B3-3=15-3\"
\n" ); document.write( "\"2y%2B0=12\"
\n" ); document.write( "\"2y=12\"
\n" ); document.write( "\"2y%2F2=12%2F2\"
\n" ); document.write( "\"y=6\"\r
\n" ); document.write( "\n" ); document.write( "Again, \"x=y%2B3\", so,\r
\n" ); document.write( "\n" ); document.write( "\"x=6%2B3=9\"\r
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\n" ); document.write( "\n" ); document.write( "Therfore, the length is 9 inches and the width is 6 inches.\r
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\n" ); document.write( "\n" ); document.write( "Power up,
\n" ); document.write( "HyperBrain!
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