document.write( "Question 1151108: Use the trigonometric identities to expand and simplify if possible.
\n" ); document.write( "For 1−cos(𝐷)/sin(𝐷)+1\r
\n" ); document.write( "\n" ); document.write( "sin(270-A) = \r
\n" ); document.write( "\n" ); document.write( "cos(B+270)= \r
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Algebra.Com's Answer #772731 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Use the trigonometric identities to expand and simplify if possible.
\n" ); document.write( "For: \r
\n" ); document.write( "\n" ); document.write( "\"%281-cos%28D%29%29%2F%28sin%28D%29%2B1%29\"-> cannot be simplified\r
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\n" ); document.write( "\n" ); document.write( "\"sin%28270-A%29\" = ...........Use the following identity : \"sin+%28s-t%29=-cos++%28s%29%2Asin%28t+%29%2B+cos%28t%29%2Asin%28s%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28270-A%29+=-+cos+%28270%29+%2Asin%28A%29%2B+cos%28A%29%2Asin%28270%29\"...........since \"cos%28270%29=0+\"and \"sin%28270%29=-1\", we have\r
\n" ); document.write( "\n" ); document.write( "\"sin%28270-A%29+=-+0%2Asin++%28A+%29%2B+cos+%28A+%29+%2A%28-1%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28270-A%29+=0-+cos+%28A+%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%28270-A%29+=-+cos+%28A+%29+\"\r
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\n" ); document.write( "\n" ); document.write( "for next one use identities above\r
\n" ); document.write( "\n" ); document.write( "\"cos%28B%2B270%29=cos%28270%29cos%28B%29+-+sin%28270%29+sin%28B%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28B%2B270%29=0%2A+cos%28B%29+-%28-1%29+sin%28B%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%28B%2B270%29=+sin%28B%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28C%2B225%29\"=............Use the following identity : \"tan%28a%29=sin%28a%29%2Fcos%28a%29\"\r
\n" ); document.write( "\n" ); document.write( "\"tan%28C%2B225%29=sin%28C%2B225%29%2Fcos%28C%2B225%29\"\r
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\n" ); document.write( "\n" ); document.write( "since \"sin%28225%29=-1%2Fsqrt%282%29+\"and \"cos%28225%29=-1%2Fsqrt%282%29\", we have\r
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\n" ); document.write( "\n" ); document.write( "\"tan%28C%2B225%29=%28+sin%28C%29%2B+cos%28C%29++%29%2F++%28sin%28C%29+-++cos%28C%29%29\"\r
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