document.write( "Question 1151111: In the diagram below, point X is the intersection of the two diagonals TW and UV of the cubical box illustrated. The shortest distance from point T to point Z is 4 sqrt3 cm. Find the area in cm2, of triangle XYZ.\r
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document.write( "Diagram: https://imgur.com/a/ciK5pIK
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Algebra.Com's Answer #772730 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "TZ is the space diagonal of the cube. Given its length as 4*sqrt(3), the side of the cube has length 4. \n" ); document.write( "Picture points A and B as the midpoints of VW and YZ, respectively. Then AB=4, AX=2, and BX is the altitude of triangle XYZ. \n" ); document.write( "Use the Pythagorean Theorem to find the length of altitude BX; then the area of triangle XYZ is one-half base times height.... \n" ); document.write( " \n" ); document.write( " |